N 1) a² − 9a + 14 = 0 Group terms that contain the same variable, and move the
constant to the opposite side of the equation(a² − 9a)=-14Complete
the square Remember to balance the equation by adding the same constants
to each side (a² − 9a+20.25)=-14+20.25 Rewrite as perfect squares(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25 a1=4.5+√6.25-----> a1=7a2=4.5-√6.25-----> a2=2the solution problem N 1 is the pair {7, 2} N 2) a² + 9a + 14 = 0 Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² + 9a)=-14Complete the square Remember to balance the equation by adding the same constants to each side (a² +9a+20.25)=-14+20.25 Rewrite as perfect squares(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25 a1=-4.5+√6.25-----> a1=-2a2=-4.5-√6.25-----> a2=-7the solution problem N 2 is the pair {-2,-7}N 3) a² + 3a − 10 = 0Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² + 3a)=10 Complete the square Remember to balance the equation by adding the same constants to each side (a² + 3a+2.25)=10+2.25 Rewrite as perfect squares(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25 a1=-1.5+√12.25-----> a1=2a2=-1.5-√12.25-----> a2=-5the solution problem N 3 is the pair {2, -5} N 4)a² + 5a − 14 = 0 Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² + 5a) =14 Complete the square Remember to balance the equation by adding the same constants to each side (a² + 5a+6.25) =14+6.25 Rewrite as perfect squares(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25 a1=-2.5+√20.25-----> a1=2a2=-2.5-√20.25-----> a2=-7the solution problem N 4 is the pair {2, -7} N 5) a² − 5a − 14 = 0Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² − 5a)=14 Complete the square Remember to balance the equation by adding the same constants to each side (a² − 5a+6.25)=14+6.25 Rewrite as perfect squares(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25 a1=2.5+√20.25-----> a1=7a2=2.5-√20.25-----> a2=-2the solution problem N 5 is the pair {7, -2}