MATH SOLVE

5 months ago

Q:
# A lottery exists where balls numbered 1 to 17 are placed in an urn. to win, you must match 6 balls chosen in the correct order, how many possible outcomes are there for this game

Accepted Solution

A:

There are 17 possible choices for the first ball, 16 possible choices for the second and so on.. until 6 balls are chosen. Multiply the number of choices together.

17×16×15×14×13×12 = 8,910,720

This is also what's called a permutation, 17 choose 6

In permutations order matters so (1,2,3) is not the same as (3,2,1).

17×16×15×14×13×12 = 8,910,720

This is also what's called a permutation, 17 choose 6

In permutations order matters so (1,2,3) is not the same as (3,2,1).